মডিউল 3 · 1-এর পাঠ 4কোর্সে 9/32~10 min
মডিউল পাঠ (1/4)
অ্যারে: অর্ডার করা তালিকা
An array is an ordered list of values. In JavaScript the elements can be of different types from each other (although in "good" code they tend to be homogeneous). It's written with square brackets:
JS
const colori = ['rosso', 'verde', 'blu'];
const misti = [1, 'due', true, null];
const vuoto = [];Reading and writing by index
Indices start at 0. The last valid index is array.length - 1.
JS
const colori = ['rosso', 'verde', 'blu'];
colori[0]; // 'rosso'
colori[2]; // 'blu'
colori[99]; // undefined ← no error, just undefined
colori.length; // 3
colori[1] = 'giallo'; // now colori is ['rosso', 'giallo', 'blu']
colori[colori.length] = 'x'; // manual push, not recommendedAdding and removing elements
The four classic methods (push / pop / unshift / shift) modify the
array in place:
JS
const a = [1, 2, 3];
a.push(4); // a = [1, 2, 3, 4], returns the new length
a.pop(); // a = [1, 2, 3], returns the removed element (4)
a.unshift(0); // a = [0, 1, 2, 3], adds at the head
a.shift(); // a = [1, 2, 3], removes from the headIncluding, searching
JS
['rosso', 'verde', 'blu'].includes('verde'); // true
['rosso', 'verde', 'blu'].indexOf('blu'); // 2
['rosso', 'verde', 'blu'].indexOf('giallo'); // -1Try it
ব্যায়াম#js.m3.l1.e1
প্রচেষ্টা: 0লোড হচ্ছে...
Given the array `numbers = [10, 20, 30, 40]`, return as the last expression the last element using length.
সম্পাদক লোড হচ্ছে...
ইঙ্গিত দেখান
The last valid index is length - 1.
সমাধান 3 প্রচেষ্টার পরে উপলব্ধ
Review exercise
ব্যায়াম#js.m3.l1.e2
প্রচেষ্টা: 0লোড হচ্ছে...
Start from `fruits = ['mela', 'pera']`. Add 'banana' at the end with push, then return the full array as the last expression: ['mela','pera','banana'].
সম্পাদক লোড হচ্ছে...
ইঙ্গিত দেখান
push mutates the array; you don't need to reassign.
সমাধান 3 প্রচেষ্টার পরে উপলব্ধ