Module lessons (3/4)
collections: Counter and defaultdict
The collections module adds specialized data types that extend the
built-in collections. The three most used: Counter, defaultdict,
namedtuple.
Counter: frequency counting
from collections import Counter
parole = ["mela", "pera", "mela", "kiwi", "mela", "pera"]
c = Counter(parole)
# Counter({'mela': 3, 'pera': 2, 'kiwi': 1})
c["mela"] # 3
c["banana"] # 0 (default for missing keys, NO KeyError)
c.most_common(2) # [('mela', 3), ('pera', 2)]It also works on strings (counts characters):
Counter("ciao mondo")
# Counter({'o': 2, 'c': 1, 'i': 1, 'a': 1, ' ': 1, 'm': 1, 'n': 1, 'd': 1})It supports set-like operations on counts (+, -, &, |) — very handy for aggregating counts from different sources.
defaultdict: dict with automatic default
A dict that, when you access a missing key, creates it by calling a factory.
from collections import defaultdict
gruppi = defaultdict(list) # factory = list (empty list)
for nome in ["Ada", "Linus", "Ada", "Grace"]:
gruppi[nome].append(1)
# defaultdict(list, {'Ada': [1, 1], 'Linus': [1], 'Grace': [1]})Without defaultdict, you would have to write:
gruppi = {}
for nome in [...]:
if nome not in gruppi:
gruppi[nome] = []
gruppi[nome].append(1)Common factories: list, int (default 0), set, dict.
namedtuple: tuples with field names
A lightweight way to create immutable record-classes. It is a tuple, but with field access by name.
from collections import namedtuple
Punto = namedtuple("Punto", ["x", "y"])
p = Punto(3, 4)
p.x # 3 (access by name)
p[0] # 3 (access by index, still a tuple)
p.x + p.y # 7
# typical use: return multiple values from a function
def divisione(a, b):
Risultato = namedtuple("Risultato", ["quoziente", "resto"])
return Risultato(a // b, a % b)
r = divisione(17, 5)
r.quoziente # 3
r.resto # 2(For more sophisticated cases there is also dataclasses since 3.7 — see M9.)
namedtuple: lightweight immutable records
The collections module also exports namedtuple, which lets you quickly build lightweight class-like objects to store structured data without writing constructors or boilerplate methods:
from collections import namedtuple
Point = namedtuple('Point', ['x', 'y'])
p = Point(10, 20)
print(p.x, p.y)Try it
Given the list `words = ['mela', 'pera', 'mela', 'kiwi', 'mela', 'pera']`, compute the most frequent word in `top` as a string. Evaluate `top`.
Show hint
Counter(...).most_common(1) returns [(word, count)].
Solution available after 3 attempts
Review exercise
Given the students `enrollments = [('Ada', 'mate'), ('Linus', 'fisica'), ('Ada', 'storia'), ('Grace', 'mate')]`, build `courses_per_student` as a defaultdict(list). Evaluate `dict(courses_per_student)`.
Show hint
defaultdict(list) then for s, c in enrollments.
Solution available after 3 attempts
Additional challenge
Import `Counter` from `collections`. Count the frequency of characters in the string `text = "abracadabra"`. Store the counter in `char_counter` and evaluate it.
Show hint
Counter takes the string as a parameter and counts the occurrences of each letter.
Solution available after 3 attempts