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变量和数据类型

In C++, every variable has a well-defined static type at compile time. This means that once you declare a variable of a certain type, you cannot change its type later.

This approach guarantees maximum performance at runtime and allows the compiler to catch many common errors before the program even runs.

Declaration and Initialization

To declare a variable in C++, you must specify the type first, followed by the name of the variable:

Code
int age; // Declaration without initialization (contains an undefined value!)
age = 25; // Subsequent assignment

Modern Initialization

Modern C++ introduces several forms of initialization. The safest and most uniform is brace initialization (introduced in C++11):

Code
int age = 25;       // Classic initialization (C-style)
int score {100};    // Uniform initialization (C++11)

Fundamental Primitive Types

Here are the main data types you will use every day:

TypeDescriptionExample
intInteger numbers (e.g. 1, -42, 0)int points = 50;
doubleDouble-precision floating-point numbersdouble price = 19.99;
charA single character enclosed in single quoteschar grade = 'A';
boolBoolean values (true or false)bool isActive = true;

Complex Objects: std::string

To manage text sequences, the C++ standard library provides the std::string class (defined in the <string> header):

Code
#include <string>

std::string name = "Alice";

Try it yourself

锻炼#cpp.m1.l1.e1
尝试:0加载中...

Declare a variable named age of type int with value 30, and print it using std::cout.

正在加载编辑器...
显示提示

Use the syntax `int age = 30;`to declare the variable, then print it with`std::cout << age;`.

3 次尝试后可用的解决方案

锻炼#cpp.m1.l1.e2
尝试:0加载中...

Declare a variable named username of type std::string with value 'Alice', and print it using std::cout.

正在加载编辑器...
显示提示

Usa `std::string username = "Alice";` e poi inviala allo stream std::cout.

3 次尝试后可用的解决方案