模块课程(3/5)
可变参数函数
Variadic functions accept an arbitrary number of arguments of the
same type. You declare them by putting ... before the type of the last
parameter. Inside the function the parameter is a slice.
Declaration
func sum(nums ...int) int {
tot := 0
for _, n := range nums {
tot += n
}
return tot
}
sum() // 0 (nums = []int{})
sum(1) // 1
sum(1, 2, 3, 4) // 10Only the last parameter can be variadic:
func log(prefix string, values ...any) { ... } // ok
// func wrong(...int, suffix string) {} // ERRORESpreading a slice
If you already have a slice, you can pass it to a variadic function with
...:
nums := []int{1, 2, 3}
sum(nums...) // 6 — espande lo slice nei singoli argomentiThe "..." goes after the slice. Without spread you'd get a type
error: you'd be passing a []int where the function expects a sequence
of int.
nums is a slice, not a new container
Inside the function nums has type []int. All standard slice
operations work: len(nums), nums[0], range, etc.
Classic use case: fmt.Println
All of fmt's Print* functions are variadic:
// signature (semplificata):
// func Println(a ...any) (n int, err error)
fmt.Println("ciao", 42, true)
args := []any{"a", "b", "c"}
fmt.Println(args...)Try it
Define sum(nums ...int) int that returns the sum of all arguments.
显示提示
Inside the function `nums` has type `[]int`.
3 次尝试后可用的解决方案
Call the existing sum function by passing the slice nums with spread `nums...`.
显示提示
The `...` goes AFTER the slice name.
3 次尝试后可用的解决方案
Inside `func f(args ...string)`, what type is `args`?
func f(args ...string) {
_ = args
}Recap
...Tas the LAST parameter = variadic function; inside it's[]T.- Called with single values: the compiler collects them into a slice.
- Called with an existing slice:
slice...(spread, reuses the slice). - All
fmt.Print*functions are variadic. - Only the last parameter can be variadic.