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模块 6 · 第 4 课(共 4)课程中的24/32~12 min
模块课程(4/4)

实践中环顾四周

Let's put all four forms of lookaround together in real-world scenarios. Lookarounds shine when you need to:

  1. Extract a value without the context that identifies it.
  2. Validate a string against multiple independent conditions.
  3. Filter matches that satisfy some conditions but not others.

Password validation

Code
Pattern: ^(?=.*[A-Z])(?=.*\d)(?=.*[^a-zA-Z\d]).{8,}$
Checks:
  - at least one uppercase     (?=.*[A-Z])
  - at least one digit         (?=.*\d)
  - at least one symbol        (?=.*[^a-zA-Z\d])
  - minimum length 8           .{8,}

Each lookahead checks one condition, starting from the beginning (^). They are all zero-width: the engine stays at position 0 and then consumes with .{8,}$.

Extraction between delimiters

Code
Pattern: (?<=\().+?(?=\))
Sample:  Funzione foo(bar) e baz(qux, qix)
Match: "bar", "quux, qix" (without parentheses)

Lookbehind + lookahead + lazy quantifier: extracts the content inside the parentheses without including them.

Combining lookahead and lookbehind

Using lookahead and lookbehind together allows isolating strings that lie within specific tags or formats (e.g. extracting text between two tags without including the tags in the final match). This avoids subsequent string cleanup operations.

Try it

锻炼#regex.m6.l4.e1
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Extract the value of every `key=value` assignment from the log: ONLY the values (no keys, no `=`). Values may contain letters and digits.

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Move `=` inside a lookbehind (?<==): this way the match contains only the value.

3 次尝试后可用的解决方案

Review exercise

锻炼#regex.m6.l4.e2
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Find which words have at least ONE uppercase letter AND at least ONE digit (in any order), locating them in the text.

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Double lookahead at the start: (?=\\w*[A-Z])(?=\\w*\\d). Then consume the word with \\w+.

3 次尝试后可用的解决方案

Additional challenge

锻炼#regex.m6.l4.e3
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Extract only numerical digits that are enclosed exactly between parentheses, e.g. extract `102` from `(102)` without capturing the parentheses.

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Combine a positive lookbehind (?<=\( ) for the open parenthesis and a positive lookahead (?=\) ) for the closed one.

3 次尝试后可用的解决方案